更新: 2008 年 7 月
由于对象是多态的,因此基类类型的变量可以保存派生类型。若要访问派生类型的方法,需要将值强制转换回该派生类型。不过,在这些情况下,如果只尝试进行简单的强制转换,会导致引发
示例
下面的示例演示如何使用 is 和 as 运算符从一个引用类型强制转换为另一个引用类型,而没有引发异常的风险。此示例还演示如何对 as 运算符使用可以为 null 值的类型。
C# | 复制代码 |
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class SafeCasting { class Animal { public void Eat() { Console.WriteLine("Eating."); } public override string ToString() { return "I am an animal."; } } class Mammal : Animal { } class Giraffe : Mammal { } class SuperNova { } static void Main() { SafeCasting app = new SafeCasting(); // Use the is operator to verify the type. // before performing a cast. Giraffe g = new Giraffe(); app.UseIsOperator(g); // Use the as operator and test for null // before referencing the variable. app.UseAsOperator(g); // Use the as operator to test // an incompatible type. SuperNova sn = new SuperNova(); app.UseAsOperator(sn); // Use the as operator with a value type. // Note the implicit conversion to int? in // the method body. int i = 5; app.UseAsWithNullable(i); double d = 9.78654; app.UseAsWithNullable(d); // Keep the console window open in debug mode. System.Console.WriteLine("Press any key to exit."); System.Console.ReadKey(); } void UseIsOperator(Animal a) { if (a is Mammal) { Mammal m = (Mammal)a; m.Eat(); } } void UseAsOperator(object o) { Mammal m = o as Mammal; if (m != null) { Console.WriteLine(m.ToString()); } else { Console.WriteLine("{0} is not a Mammal", o.GetType().Name); } } void UseAsWithNullable(System.ValueType val) { int? j = val as int?; if (j != null) { Console.WriteLine(j); } else { Console.WriteLine("Could not convert " + val.ToString()); } } } |
请参见
修订记录
日期 | 历史记录 | 原因 |
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2008 年 7 月 | 新增主题。 |
内容 Bug 修复 |